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Solution :

Decrease in concentration <br> ` Delta A = [ 0.5 - 0.4 ] mol L^(-1) = 0.1 mol L^(-1)` <br> time interval = 10 min <br> Rate of reaction = `1/2` Rate of disappearance of <br> ` A= 1/2 . (Delta [A] )/( Delta t) = 1/2 xx (0.1 )/( 10 ) = 0.005 M min""^(-1)`