Abstract.
We solve the currently smallest open case in the 1976 problem of Molluzzo on , namely the case
. This amounts to constructing, for all positive integers n congruent to 0 or 7 mod 8, a sequence of integers modulo 4 of length n generating, by Pascal's rule, a Steinhaus triangle containing 0, 1, 2, 3 with equal multiplicities.
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