1 Introduction
Let ℕ = {1, 2, ..., n, ..} and ℤ be the set of integers. A subset S of the set ℕ of nonnegative integers is called a numerical semigroup if it satisfies the following conditions:
- (i)0 ∈ S,
- (ii)a, b ∈ S ⇒ a + b ∈ S,
- (iii)ℕ \ S has a finite number of elements.
Condition (iii) is equivalent to gcd(S) = 1 (Here, gcd(S) is the greatest common divisor of the element of S).
F ( S ) and n ( S ) are called the Frobenius number of S and the number determiner of S, respectively.
If a numerical semigroup S satisfies the condition x + y − z ∈ S, for every x, y, z ∈ S such that x ≥ y ≥ z, then S is called Arf. If S is an Arf numerical semigroup, then S has maximal embedding dimension.
In this study, we show that all families of numerical semigroups with multiplicity four are saturated numerical semigroups; these are numerical semigroups of the form S = 〈4, k, k + 2, k + 3〉, for k = 3(mod4) and k ≥ 7 and S = 〈4, k, k + t, k + t + 2〉, for k = 2(mod 4) and k ≥ 6 and t an odd integer. We also give the formulae for F(S), n(S), PF(S), g(S), H(S) and FH(S) of these numerical semigroups.
2 Main results
In this section we provide some results for numerical semigroups with multiplicity four; i.e. numerical semigroups of the form S = 〈4, k, k + 2, k + 3〉 (for k ≡ 3(mod 4) and k ≥ 7) and S = 〈4, k, k + t, k + t + 2〉, (for k ≡ 2(mod 4) and k ≥ 6 and t an odd integer).
([8]).Let S be a numerical semigroup, then the following conditions are equivalent:
- (i)S is a saturated numerical semigroup.
- (ii)a + dS(a) ∈ S for all a ∈ S, a > 0 where dS(a) = gcd{x ∈ S : x ≤a }.
- (iii)a + kdS(a) ∈ S for all a ∈ S, a > 0 and k ∈ ℕ.
([10]). If S = 〈4,k, k + 1, k + 2 〉 , then S is a saturated numerical semigroup, for k ≡ 1(mod 4) and k ≥ 5.
Let S = 〈4, k, k + 2, k + 3〉 be numerical semigroup, where k ≡ 3( mod 4) and k ≥ 7. Then S is saturated.
In this case,
- (a)If a < 4r + 3, then dS(a) = 1. So, we find that a + dS(a) ∈ S since a + dS(a) = a + 1 ≥ 4r + 4 ∈ S, for all a ∈ S, a > 0.
- (b)If a ≥ 4r + 3, then dS(a) = 4. So, we have a + dS(a) = a + 4 ∈ S, for all a ∈ S, a > 0.
In view of Proposition 2.1, we find that S is saturated a numerical semigroup. □
Let S = 〈4,k, k + t, k + t + 2〉 be numerical semigroup, where k ≡ 2(mod 4), k ≥ 6, and t is an odd integer. Then S is saturated.
In this case,
- (i)If a > 4r + t + 1, then dS(a) = 1. So, we obtain a + dS(a) ∈ S from the inequality a + dS(a) = a + 1 ≥ 4r + t + 2 ∈ S, for all a ∈ S, a > 0.
- (ii)If 4r ≤ a ≤ 4r + t + 1, then dS(a) = 2. So, we obtain a + dS(a) = a + 2 ∈ S from the inequality 4r ≤ a ≤ 4r + t + 1, for all a ∈ S, a > 0.
- (iii)If a < 4r, then dS(a) = 4. So, we obtain a + dS(a) = a + 4 ∈ S since a + 4r < 4r + 4, for all a ∈ S, a > 0.
In view of Proposition 2.1, we have that S is a saturated numerical semigroup. □
([6]).Let S be a numerical semigroup minimally generated by {n1 < n2 < ... < nr}. Then S has maximal embedding dimension if and only if Ap(S, n1) = {0,n2, n3,...,nr}.
([6]).Let S be a numerical semigroup minimally generated by {n1 < n2 < ... < nr}. Then the following conditions are true:
- (1)If S has maximal embedding dimension, then F(S) = nr − n1.
- (2)S has maximal embedding dimension if and only if
If S = 〈4, k k + 2, k + 3〉 is a numerical semigroup, where k ≡ 3(mod 4) and k ≡ 7. Then we obtain following equalities:
- (a)F(S) = k − 1,
- (b)
, - (c)PF(S) = {k − 4, k − 2, k − 1},
- (d)
, - (e)H(S) = {1, 2, 3, 5, 6, 7, ... , k − 6, k − 5, 5k − 4, k − 2, k − 1}.
We have Ap(S, 4) = {0, k, k − 2, k − 3} since S has maximal embedding dimension. Thus,
- (a)We have F(S) = (k + 3) − 4 = k − 1 from Corollary 2.6 (1).
- (b)We obtain
from Corollary 2.6 (2). - (c)It is obvious that PF(S) = {k − 4, k + 2 − 4, k + 3 − 4}. So we find PF(S) = { k − 4, k − 2, k − 1}.
- (d)We have
from g(S) = F(S) + 1 − n(S). - (e)We find that H(S) = {1, 2, 3, 5, 6, 7, ... , 4r − 3, 4r − 2, 4r − 1, 4r + 1, 4r + 2} = {1, 2, 3, 5, 6, 7, ... , k − 6, k − 5, k − 4, k − 2, k − 1} from the equality S = < 4, k, k + 2, k + 3 > {0, 4, 8, ... , k − 7, k − 3, k, → ... ,} = {0, 4, 8, ... , 4r − 4, 4r, 4r − 3, → ... ,}.
Let S= 〈4, k, k + t, k + t + 2〉 be a numerical semigroup, where k ≡ 2(mod 4), k ≡ 6, and t is an odd integer. Then, we have following equalities:
- (a)F(S) = k + t − 2,
- (b)
, - (c)PF(S) = {k − 4, k + t − 4, k + t − 2},
- (d)
, - (e)H(S) = {1, 2, 3, 5, 6, 7, ... , k − 5, k − 4, k − 3, k − 1, k − 1, k + 3, ... , k + t − 2}.
We have Ap(S, 4) = {0, k, k + t, k + t + 2} since S has maximal embedding dimension. Thus,
- (a)We have F(S) = (k + t + 2) − 4 = k + t + 2 from Corollary 2.6 (1).
- (b)We obtain
from Corollary 2.6 (2). - (c)It is obvious that PF(S) = {k − 4, k + t − 4, k + t − 2 − 4}. So, we find PF(S) = {k − 4, k + t − 4, k + t − 2}.
- (d)We have
from g(S) = F(S) + 1 − n(S). - (e)We observe that H(S) = {1, 2, 3, 5, 6, 7, ... , 4r − 3, 4r − 2, 4r − 1, 4r − 1, 4r + 3, 4r + 5, ... , 4r + t} = {1, 2, 3, 5, 6, 7, ... , k − 5, k − 4, k − 3, k − 1, k + 1, k + 3, ... , k + t + 2} since S= 〈4, k, k + t, k + t + 2〉 = {0, 4, 8, ... , k − 6, k − 2, k, k + 2, ... , k + t − 3, k + t − 1, → ... ,} = {0, 4, 8, ... ,4r − 4, 4r, 4r + 2, 4r + 4, ... , 4r − t − 1, 4r + t + 1, → ... ,}.
Consider the numerical semigroup S= 〈4, k, k + 2, k + 3〉. If we put k = 15 then we have that S = 〈4, k, k + 2, k + 3〉 = 〈4, 15, 17, 18〉 = {0, 4, 8, 12, 15, → ... ,} is saturated. Hence, we find that
- (a)F(S) = k − 1 = 15 − 1 = 14,
- (b)
, - (c)PF(S) = {k − 4, k − 2, k − 1} = {11, 13, 14},
- (d)
, - (e)H(S) = {1, 2, 3, 5, 6, 7, ... , k − 6, k − 5, k − 4, k − 2, k − 1} = {1, 2, 3, 5, 6, 7, 9, 10, 11, 13, 14} and Ap(S, 4) = {0, k, k + 2, k + 3} = {0, 15, 17, 18}.
Consider the numerical semigroup S= 〈4, k, k + t, k + t + 2〉. If we put k = 14 and t = 13 then we find that S= 〈4, k, k + t, k + t + 2〉 = 〈4, 14, 27, 29〉 = {0, 4, 8, 12, 14, 16, 18, 20, 22, 24, 26, → ... ,} is saturated. Thus, we observe that
- (a)F(S) = k + t − 2 = 14 + 13 − 2 = 25,
- (b)
, - (c)PF(S) = {k − 4, k + t − 4, k + t − 2} = {10, 23, 25},
- (d)
, - (e)H(S) = {1, 2, 3, 5, 6, 7, ... , k − 5, k − 4, k + 3, k − 1, k − 1, k +3, ... , k − t − 2} = {1, 2, 3, 5, 6, 7, 9, 10, 11, 13, 15, 17, 19, 21, 23, 25} and Ap(S, 4) = {0, k, k + t, k + t + 2} = {0, 14, 27, 29}.
The authors thank the anonymous referee for his/her remarks which helped them to improve the presentation of the paper.
References
- [1]↑
Abawajy J., Kelarev A.V., Chowdhury M., Power graphs: a survey, Electronic J. Graph Theory and Applications, 2013, 1(2), 125-147
- [2]↑
Barucci V, Dobbs D.E., Fontana M., Maximality properties in numerical semigroups and applications to one-dimensional analytically irreducible local domains,Memoirs of American Mathematical Society 1997, 125(598), 1-77
- [3]↑
Kelarev A.V., Combinatorial properties of sequences in groups and semigroups, "Combinatorics, Complexity and Logic", Discrete Mathematics and Theoretical Computer Science, 1996, 289-298
- [5]↑
Kelarev A.V., Ryan J., Yearwood J., Cayley graphs as classifiers for data mining:The influence of asymmetries, Discrete Mathematics, 2009, 309(17), 5360-5369
- [7]↑
Rosales J.C., Garcia-Sánchez P.A., Garcia-Garcia J.I., Jimenez Madrid J.A., Fundamental gaps in numerical semigroups, Journal Pure and Applied Algebra, 2004, 189, 301-313
- [8]↑
Rosales J.C., Garcia-Sánchez P.A., Garcia-Garcia J.I., Branco M.B., Saturated numerical semigroups, Houston J.of Math. 2004, 30, 321-330
- [9]↑
Rosales J.C., Numerical Semigroups with Apery sets of unique expression, Journal of Algebra, 2000, 226, 479-487
- [10]↑
Suer M., Ilhan S., On a family of saturated numerical semigroup with multiplicity four, Turkish Journal of Math., (in press), DOI:10.3906