It is known that there is a continuous linear functional on L
∞ which is not narrow. On the other hand, every order-to-norm continuous AM-compact operator from L
∞(μ) to a Banach space is narrow. We study order-to-norm continuous operators acting from L
∞(μ) with a finite atomless measure μ to a Banach space. One of our main results asserts that every order-to-norm continuous operator from L
∞(μ) to c
0(Γ) is narrow while not every such an operator is AM-compact.
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